Jarkom (IP v4)

11 05 2010
  1. 192.168.11.25/24

    2. a. Subnet Mask
    = 11111111.11111111.11111111.00000000
    = 255.255.255.0

    b. Network ID
    11000000.10101000.00001011.00011001 = IP
    11111111.11111111.11111111.00000000 = Net Mask
    …………………………………………………………………………………..AND
    11000000.10101000.00001011.00000000
    = 192.168.11.0

    c. Host ID = 25

    d. Broadcast ID
    11000000.10101000.00001011.00000000 = Net ID
    11111111.11111111.11111111.00000000 = Net Mask
    ……………………………………………………………………………………OR
    11000000.10101000.00001011.11111111
    = 192.168.11.255

    e. Kelas = C
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